Tennis Women: Fed Cup 1988 at Melbourne (aus) December 4-11: 2nd Round: Australia * - Italy 3-0 Canada * - Finland 3-0 Czechoslovakia * - New Zealand 3-0 Denmark * - Argentina 2-1 Soviet Union * - Austria 2-1 Spain * - Indonesia 3-0 Sweden * - USA 2-1 West Germany * - France 3-0 Quarterfinals: Canada * - Sweden 3-0 Czechoslovakia * - Denmark 3-0 Soviet Union * - Spain 2-1 West Germany * - Australia 2-1 Semifinals: Czechoslovakia * - Canada 3-0 Soviet Union * - West Germany 2-1 Final: Czechoslovakia * - Soviet Union 2-1 (Radomila Zrubaková (czs) - Larisa Savchenko (sov) 6-1 7-6(7-2), Helena Suková (czs) - Natalya Zvereva (sov) 6-3 6-4, Soviet Union (Larisa Savchenko, Natalya Zvereva) - Czechoslovakia (Jana Pospilová, Jana Novotna) 7-6(7-5) 7-5)